in aΔABC, if AB=AC and angle B=65°find angle A
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Answered by
1
heya.........
if AB = AC
angle B = angle C ( angles opposite to equal sides are also equal )
angle A + angle B + angle C = 180
65+65+a = 180
a + 130 = 180
a = 50
hope it helps
if AB = AC
angle B = angle C ( angles opposite to equal sides are also equal )
angle A + angle B + angle C = 180
65+65+a = 180
a + 130 = 180
a = 50
hope it helps
Answered by
0
Heya....!!!
HERE IS YOUR ANSWER
--------------------------------------------------
In ΔABC,
AB = AC ...........(given)
Angle B = 65° ................(given)
Angle B = Angle C
(angles opposite to equal sides are equal)
Angle C = 65°
Angle A + Angle B + Angle C = 180°
(as the sum of all angles of triangle = 180°)
Angle A + 65° + 65° = 180°
Angle A + 130° = 180°
Angle A = 180°-130°
Angle A = 50°
--------------------------------------------------------
HOPE IT HELPS!!!!!
HERE IS YOUR ANSWER
--------------------------------------------------
In ΔABC,
AB = AC ...........(given)
Angle B = 65° ................(given)
Angle B = Angle C
(angles opposite to equal sides are equal)
Angle C = 65°
Angle A + Angle B + Angle C = 180°
(as the sum of all angles of triangle = 180°)
Angle A + 65° + 65° = 180°
Angle A + 130° = 180°
Angle A = 180°-130°
Angle A = 50°
--------------------------------------------------------
HOPE IT HELPS!!!!!
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