Question

In a ∆ABC, if AB + BC = 12 cm, BC + CA = 14 cm, CA + AB = 18 cm, then the perimeter of the triangle is​

Answer 1

AB + BC = 12
BC + CA = 14
CA + AB = 18
2(AB+BC+CA)=44
​

AB + BC + CA =22 cm
∴ Perimeter = 22 cm

Answer 2

Answer:

Perimeter of ΔABC = 22 cm.

Step-by-step explanation:

Here sides AB, BC & CA are repeated twice.

∴2 (AB + BC + CA) = 12 + 14 + 18

∴2 (AB + BC + CA) = 44

Then, AB + BC + CA = 44/2

∴ AB + BC + CA = 22.

∵ Perimeter of ΔABC = 22 cm