In a Δ ABC, if AB =BC 120° and ∠B = 70°, Find ∠A.
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Given : In a Δ ABC, if AB = AC and ∠B = 70°. [Mistake in the question]
Δ ABC is an isosceles triangle since AB = AC.
∠B = ∠C = 70°
[Angles opposite to equal sides are equal]
We know, that sum of angles in a triangle is 180° :
∠ A + ∠ B + ∠ C = 180°
∠A + 70° + 70° = 180°
∠A + 140° = 180°
∠A = 180° - 140°
∠A = 40°
Hence, ∠ A = 45°.
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