Question

In a ∆ABC if angle A = 45°and angle B is 70° determine the shortest side of the triangle?
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Answer 1

Answer:

in given question in ∆ ABC we have

•Angle [A] = 45°

•Angle [B] = 70°

~we know that the sum of all sides of triangle is = 180°

so, let angle c = x

then, angle a + angle b + angle c = 180°

~ 45° + 70° + x = 180°

~. 115° + x = 180°

~ x = 180° - 115°

~ x = 65°

Hence angle c = 65° as shown as ......

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