In a ∆ABC, if angle A =72° and angle B =65°, find the measure of angle C.
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Total measure of triangle=180
let x be the angle c
72+65+x=180°
x=180°-137°
=43°
let x be the angle c
72+65+x=180°
x=180°-137°
=43°
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Answered by
2
As we know,
Sum of angle of triangle is 180°
Then,
Angle A+AngleB+AngleC=180°
72°+65°+x=180°
137°+x=180°
x=180°-137°
x=43°
Thus Angle C is 43°
Sum of angle of triangle is 180°
Then,
Angle A+AngleB+AngleC=180°
72°+65°+x=180°
137°+x=180°
x=180°-137°
x=43°
Thus Angle C is 43°
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