Question

In a ∆ ABC if two angle A = 3 angle B = 6 angle C then find angle A angle B and angle C.

Answer 1

Answer:

Step-by-step explanation:

2angleA=3angleB=6angleC

=angleA+angleB+angleC=180(angle sum property) ----eq1

let x=2angleA=3angleB=6angleC

x=2angleA. x/2=angleA. ----eq2

x=3angleB. x/3=angleB. ----eq3

x=6angleC. x/6=angleC. ----eq4

substituting eq2,3,4 in eq1

x/2+x/3+x/6=180

Lcm=6

3x+2x+x/6=180

6x=180×6

6x=1080

x=180------eq 5

substituting eq 5 in eq 2,3,4

angleA=x/2=90

angleB=x/3=60

angleC=x/6=30

hope this helps

Answer 2

Step-by-step explanation:

2<A=3<B=6<C

2<A=6<C

<A=3<C

3<B=6<C

<B=6<C/3. => <B=2<C

In triangle ABC

<A+<B+<C=180°

3<C+2<C+>C=180°

6<C=180°

<C=30°

<A=3<C

=3×30. =90°

<B=2<C=2×30 =60°