Question

In a ∆ABC, if2 ∆A = 3 ∆B=6Z ∆C, calculate ∆A, ∆B and ∆C?​

Answer 1

Step-by-step explanation:

$let \: 2 < a = 3 < b = 6 < c \: be \:x$

$< a = \frac{x}{2} < b = \frac{x}{3} < c = \frac{x}{6}$

$we \: know \: that \: sum \: of \: all \: angles \\ \: of \: triangle = 180$

$< a + < b + < c = 180$

$\frac{x}{2} + \frac{x}{3} + \frac{x}{6} = 180$

$\frac{3x + 2x + x}{6} = 180$

$\frac{6x}{6} = 180$

$x = \frac{180 \times 6}{6}$

$x = 180$

$< a = \frac{180}{2} = 90 \\ < b = \frac{180}{3} = 60 \\ < c = \frac{180}{6} = 30$