Question

In a ΔABC is 2ΔA= 3ΔB = 6ΔC calculate ΔA,ΔB,ΔC​

Answer 1

Step-by-step explanation:

let

2A = 3B = 6C = K ( constant )

A = K/2

B = K/3

C = K/6

In triangle ABC

A + B + C = 180

K/2 + K/3 + K/6 = 180

3K + 2K + K = 180 × 6

6K = 1080

K = 180

A = K/2 = 180/2 = 90

B = K/3 = 180/3 = 60

C = K/6 = 180/6 = 30

Hope it helps i