In a ∆ABC it is given that AB=√3cm, AC=2cm & AD is the bisector of angle A then, BD:DC?
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Answer:
Correct option is
C
3:4
In △ABC,
AD bisects ∠A
By angle bisector theorem,
AC
AB
=
DC
BD
DC
BD
=
4
3
Answered by
0
Given:
AB= √3cm
AC= 2cm
AD bisects angle A
To find:
BD:DC
Solution:
We can find the ratio by following the given steps-
We know that the angle bisector cuts the side opposite to the angle in the ratio of sides containing it. (Angle-Bisector Theorem)
So, the ratio of AB and AC is equal to the ratio of BD and DC.
AB/AC=BD/DC
√3/2=BD/DC
Therefore, BD:DC=√3:2.
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