Math, asked by tiwarianamika, 23 hours ago

In a ∆ABC it is given that AB=√3cm, AC=2cm & AD is the bisector of angle A then, BD:DC?​

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Answers

Answered by ksimarpreet106
5

Answer:

Correct option is

C

3:4

In △ABC,

AD bisects ∠A

By angle bisector theorem,

AC

AB

=

DC

BD

DC

BD

=

4

3

Answered by Anonymous
0

Given:

AB= √3cm

AC= 2cm

AD bisects angle A

To find:

BD:DC

Solution:

We can find the ratio by following the given steps-

We know that the angle bisector cuts the side opposite to the angle in the ratio of sides containing it. (Angle-Bisector Theorem)

So, the ratio of AB and AC is equal to the ratio of BD and DC.

AB/AC=BD/DC

√3/2=BD/DC

Therefore, BD:DC=√3:2.

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