Question

In a ∆ ABC < ABC=30°, < BCA =75° find < BAC​

Answer 1

Sum of angles of a triangle = 180°

<ABC+<bca+<bac = 180°

30 + 75 + ang bac = 180°

105+ angbac = 180°

ang bac = 180-105

= 75°

Answer 2

ABC =30 and angle BCA = 75

then find the BAC

so, 30+75=180

180=105

angle BAC= 75