Question

in a ABC, <c=3<B=2(<a+<B). Find three angles​

Answer 1

Answer:

let angle A=x

Angle B=y

As mentioned in the question angle C= 3 angle B = 3y

Angle C is also given as (Angle A + Angle B)=2(x+y)

so,

3y = 2(x+y)

y=2x

so angle C=3y = 6x

we know that sum of all the 3 angles in a triangle = 180deg

Therefore

Angle A+Angle B+Angle C = 180

x+ 2x+ 6x = 180

x=20

Hence Angle A =20

Angle B =40

Angle C = 120

Answer 2

Answer:

angle b =40

Step-by-step explanation:

angle c =130