In a Δ ABC, P, Q and R are the midpoints of sides BC, CA and AB respectively. If AC=21cm, BC=29cm, AB = 30cm find the perimeter of the quadrilateral ARPQ.
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If R, Q and P are the midpoints of AB, AC and BC, and by applying the theorem:-
The line segment joining the midpoints of two side of a triangle is parallel to the third side and equal to half of it, we get
PQ=
2
1
AB=AR and PQ∣∣AR
PQ=
2
1
AC=AQ and PR∣∣AQ
Since the above conditions are sufficient for a parallelogram, therefore ARPQ is a parallelogram.
∴ Perimeter of ∥
gm
=ARPQ=2(AR+AQ)=AB+AC=(30+21)cm=51cm
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