In A ABC, points M and N lie on AB
and AC respectively and MN || BC. If
AM = x + 1. MB = x, AN = 3x - 3 and
NC = 4x - 10, find the value of x. 5
Answers
Answered by
24
Step-by-step explanation:
MN is parallel to BC
AM/MB =AN/NC
x+1/x =3x-3/4x-10
(x+1)(4x-10)=x(3x-3)
4x^2-6x-10=3x^2-3x
x^2-3x-10=0
x^2-5x+2x-10=0
x(x-5)+2(x-5)=0
(x-5)(x+2)=0
x=5
Answered by
4
Answer:
MN is parallel to BC
AM/MB =AN/NC
x+1/x =3x-3/4x-10
(x+1)(4x-10)=x(3x-3)
4x^2-6x-10=3x^2-3x
x^2-3x-10=0
x^2-5x+2x-10=0
x(x-5)+2(x-5)=0
(x-5)(x+2)=0
x=5
Step-by-step explanation:
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