In A ABC, PQ || BC, A-P-B, A-Q-C, AP= 2.4
cm, PB=7.2 cm, QC=5.4 cm, then find AO
1.8 cm
1.6 cm
2.2 cm
1.4 cm
Answers
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CORRECT QUESTION:-
- In △ABC, PQ || BC, A-P-B, A-Q-C, AP= 2.4cm, PB=7.2 cm, QC=5.4 cm, then find AQ.
ANSWER:-
- AQ = 1.8 cm
GIVEN:-
- ABC is a triangle.
- PQ || BC
- A-P-B, A-Q-C.
- AP = 2.4cm, PB = 7.2cm, QC = 5.4cm.
TO FIND:-
- Value of AQ.
SOLUTION:-
→ PQ || BC
→ ∠APQ = ∠ABC
→ ∠AQP = ∠ACB (corresponding angle are same)
∴ △APQ∼△ABC(AA criteria)
According to the question:-
Hence, AP/AB = AQ/AC
⇒ AB/AP = AC/AQ
⇒ AB/AP - 1 = AC/AQ - 1
⇒ PB/AP = QC/AQ
⇒ 7.2/2.4 = 5.4/AQ
⇒ AQ = 1.8cm
Hence,
- AQ = 1.8cm
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