Question

In a ∆abc right angle triangle at B, if sin A= 1/2
the value of sin C X cos A cos C Sin A (2) cos H sin A sin C​

Answer 1

Answer:

Step-by-step explanation:

given sin A =1/2 A is 30 degrees

angle B is 90 degrees

then value of angle C is 180-(90+30)=60 degrees

sin C is sin 60 is √3/2

cos C is cos 60 1/2

sin A is sin 30 =1/2

cos A is cos 30=√3/2

sinC.cosA-cosC.sinA=√3/2*√3/2-1/2*1/2

=3/4-1/4=1/2

cos A.cosC+ sinA.sinC=√3/2*1/2+1/2*√3/2

=√3/4+√3/4=2√3/4=√3/2

I hope it helps you