In A ABC right angled at A. AD is drawn such that ZDAB ZBCA, If BD = 24 cm and DC = 3 cm. find AB.
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Answer:
Given: In the above figure [B & C are swapped in the figure],
CD=24cm, BD=3cm
m<DAC=m<CBA.
RTF: AC=?
Solution:
In the given triangle, AD²=BD*CD=24*3=72 => AD=6√2cm. AC=√(AD²+CD²)=√(72+576)=√648≈25.456cm
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