Question

In A ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:
(1) sin A, cos A
(ü) sin C, cos C​

Answer 1

Answer:

ANSWER

R.E.F image

In Δ ABC, B is at right angle.

Given, AB=24cm

BC=7cm

using Pythagoras theorem 

AB2+BC2=AC2

⇒(24)2+(7)2=AC2

⇒AC=(242)+(7)2=576+49=625

⇒AC=25CM

(i)sin A=ACBC

=257

cos A=ACAB

=2524

(ii)sin C=ACAB

=2524

cos c=ACBC

=257   

Answer 2

Step-by-step explanation:

ANSWER

R.E.F image

In Δ ABC, B is at right angle.

Given, AB=24cm

BC=7cm

using Pythagoras theorem 

AB2+BC2=AC2

⇒(24)2+(7)2=AC2

⇒AC=(242)+(7)2=576+49=625

⇒AC=25CM

(i)sin A=ACBC

=257

cos A=ACAB

=2524

(ii)sin C=ACAB

=2524

cos c=ACBC

=257