In A ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:
(1) sin A, cos A
(ü) sin C, cos C
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In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB2+BC2=AC2
⇒(24)2+(7)2=AC2
⇒AC=(242)+(7)2=576+49=625
⇒AC=25CM
(i)sin A=ACBC
=257
cos A=ACAB
=2524
(ii)sin C=ACAB
=2524
cos c=ACBC
=257
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Step-by-step explanation:
ANSWER
R.E.F image
In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB2+BC2=AC2
⇒(24)2+(7)2=AC2
⇒AC=(242)+(7)2=576+49=625
⇒AC=25CM
(i)sin A=ACBC
=257
cos A=ACAB
=2524
(ii)sin C=ACAB
=2524
cos c=ACBC
=257
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