Question

In a ΔABC, right angled at B, AB=24 cm, BC=7 cm. Determine AC​

Answer 1

(AC)^2 = (AB)^2 + (BC)^2

(AC)^2 = (24)^2 + (7)^2

(AC)^2 = 576 + 49

(AC)^2 = 625

AC = √625

AC = 25 cm

Answer 2

Answer:

Given:-

In a ΔABC, right angled at B, AB=24 cm, BC=7 cm.

To Find:-

Length of AC.

Analysis:-

According to pythagorean theorem:

It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.

● Here we have AC as hypotenuse and AB and BC as other two sides...!!

Here We Go:-

AB= 24 cm

BC= 7 cm

AC = (AB)^2+(BC)^2

➡ ${24}^{2} + {7}^{2}$

➡576+49

=625

$\sqrt{625} = 25$

.°. The length of AC in a triangle ABC is 25 cm.