Question

In a ΔABC, right angled at
B, AB=24 cm, BC=7 cm
Find AC
By using Pythagoras theorem

Answer 1

Step-by-step explanation:

AB^2+,BC^2=AC^2

24^2+7^2=AC^2

625=AC^2

AC=25cm

hope this helps you better

Answer 2

Given:-  

• AB = 24 cm
• BC = 7 cm

To find:-    

• AC

Formula Used:-    

• $\boxed{\tt{(\:Hypotenuse\:)^{2}\:=\:(\:Height\:)^{2}\:+\:(\:Base\:)^{2}}}$

Where,

• AC = ( Hypotenuse )²
• AB = ( Height )²
• BC = ( Base )²

• $\boxed{\tt{(\:AC\:)^{2}\:=\:(\:AB\:)^{2}\:+\:(\:BC\:)^{2}}}$

Solution:-    

~Applying Pythagoras theorem

$\qquad\tt{:\implies\:(\:Hypotenuse\:)^{2}\:=\:(\:Height\:)^{2}\:+\:(\:Base\:)^{2}}$

$\qquad\tt{:\implies\:(\:AC\:)^{2}\:=\:(\:AB\:)^{2}\:+\:(\:BC\:)^{2}}$

$\qquad\tt{:\implies\:(\:AC\:)^{2}\:=\:(\:24\:)^{2}\:+\:(\:7\:)^{2}}$

$\qquad\tt{:\implies\:(\:AC\:)^{2}\:=\:576\:+\:49}$

$\qquad\tt{:\implies\:(\:AC\:)^{2}\:=\:625}$

$\qquad\tt{:\implies\:\:AC\:\:=\:\sqrt{625}}$

$\qquad\tt{:\implies\:AC\:=\:25\:cm}$

Therefore AC = 25 cm.