Math, asked by pasuladivyaaa, 8 months ago

In a Δ ABC, right angled at B, if AB =4, BC = 3 then Sin A = ______________


Answers

Answered by shivnagchauhan
0

Answer:

SINA= 3/5

Step-by-step explanation:

ZB=90

AB=4,BC =3

AC^2=AB^2+BC^2

AC^2=(4)^2+(3)^2

AC^2=16+9

AC^2=25

AC√25

AC=5

SINA = BC/AC= 3/5

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