In a Δ ABC, right angled at B, if AB =4, BC = 3 then Sin A = ______________
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Answer:
SINA= 3/5
Step-by-step explanation:
ZB=90
AB=4,BC =3
AC^2=AB^2+BC^2
AC^2=(4)^2+(3)^2
AC^2=16+9
AC^2=25
AC√25
AC=5
SINA = BC/AC= 3/5
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