In a ∆ABC, right angled at B, if AB=4cm and BC=3cm find sinA,cosA,tanA,cosecA,secA,cotA
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Answer:
SinA=4/5;,cosA=3/5,tanA=4/3,cosecA=5/4,secA=5/3,cotA=3/4
Step-by-step explanation:
In a right angled triangle
AC^2=AB^2+BC^2 by pythogorus theorem
AC=✓4^2+3^2=√25=5
AB=p,BC =b,AC= h
SinA=4/5;,cosA=3/5,tanA=4/3,cosecA=5/4,secA=5/3,cotA=3/4.
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