Question

in a∆ABC Right angled at b.if cot a=1/3 find:-length AC,cot B and cosec C​

Answer 1

By Pythagoras theorem, we have 

AC2=AB2+BC2

TRIGONOMETRICRATIOS

⇒AC2=122+52

⇒AC2=169

⇒AC=13

When we consider t-ratios of ∠C, we have 

Base = BC = 5, Perpendicular = AB = 12 and, Hypotenuse = AC = 13

∴cosC=HypotenuseBase=135andcotC=PerpendicularBase=PerpendicularBase=125