Question

In A ABC, Seg PQ || Seg BC A-P- B,A--Q-C AABC-AAPQ by ______test​

Answer 1

Answer:

ΔAPQ∼ΔABCby (AA) test

Step-by-step explanation:

ΔAPQ∼ΔABC by (AA) test

$\frac{Ar(APQ)}{Ar(ABC)} = \frac{AP ^2}{AB^2}$