Question

In a ABC tan A+tan B + tan C =6, and tan A tan B = 2 then the triangle ABC is

Answer 1

solutions

A+B+C=180

A+B=180−C

tan(A+B)=−tanC

(tanA+tanB) / (1−tanAtanB) =−tanC

tanA+tanB+tanC=tanAtanBtanC=6

Now, tanC=3. So, the angle C is acute.

tanA+tanB=3

tanA.tanB=2

∴tanA=2,tanB=1

A and B are also acute.

Therefore, it is acute angled triangle.

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Answer 2

Step-by-step explanation:

tan C =3

tan B =2

tan A = 1

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