In a ∆ABC,tanA and tanB satisfy the inequation√3x²-4x+√3,then
(1) a²+b²-ab<c²
(2)a²+b²>c²
(3)a²+b²+ab<c²
(4)a²+b²=c²
Answers
Answered by
3
Answer:
a×a+b×b+ab<c×c is the answer
Answered by
0
Answer:
option (3)is right answer.
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