Question

IN A ∆ABC THE ANGLE BISECTOR OF ANGLE A MEETS BC AT D then, I) AB/AC=BD/DC II) AB/DC=AC/BD iii) AB/AC=DC/BD iv) AC/AB=BD/BC


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Answer 1

Step-by-step explanation:

In ∆ ABC ; Angle bisectors of < A meets BC.

So, The correct ans is - I ) AB /AC = BD / DC

( By angle bisector theorem )...

It says that Ratio of two sides of a triangle is equal to the bisected sides proportion...