Math, asked by Sandeep543, 1 month ago

In a ∆ABC, the bisectors of angle ABC and angle ACB meet at O. Through A, AP and AQ are drawn parallel to OB and OC respectively to meet BC produced (on both sides) at P and Q respectively. Show that the perimeter of ∆ABC is equal to PQ.​

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Answered by rashikvaghela127
1

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In a ∆ABC, the bisectors of angle ABC and angle ACB meet at O. Through A, AP and AQ are drawn parallel to OB and OC respectively to meet BC produced (on both sides) at P and Q respectively. Show that the perimeter of ∆ABC is equal to PQ.

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