In a ∆ABC, the bisectors of angle ABC and angle ACB meet at O. Through A, AP and AQ are drawn parallel to OB and OC respectively to meet BC produced (on both sides) at P and Q respectively. Show that the perimeter of ∆ABC is equal to PQ.
Answers
Answered by
2
Step-by-step explanation:
this is the answer of this question
Attachments:
Answered by
5
Heya mate here is ur detailed explanation....
Attachments:
Similar questions