Question

In a ∆ABC the bisectors of angle b and angle c meet at p . if angle a = 76° find the measure of angle BPC​

Answer 1

Answer:

Ans:-152°

In ∆ABC,

Angle 'p' is twice of angle 'BAC'

BPC=2×BAC

BPC=2×76=152°

Answer 2

Answer :-

Given :-

• P is the mid point of bisectors of B and C

• ∠A = 76°

To Find :-

• ∠ BPC

Solution :-

According to the theorem :-

➩ $\rm \angle BPC = 90 + \frac{1}{2} \angle A$

So,

➩ $\rm \angle BPC = 90 + \frac{1}{2} \times 76$

➩ $\rm \angle BPC = 90 + 38$

➩ $\rm \angle BPC = 128$

Hence, ∠BPC = 128°