Math, asked by rajni123kripan, 10 months ago

In A ABC, ZA: ZB: ZC = 2:3:5. then angle at
B is​

Answers

Answered by viraajrao05
1

Answer:

let angles be 2x +3x+5x

∠A+∠B+∠C=180° (ASP of triangle)

2x+3x+5x=180°

10x=180°

x=18°

∴∠A=2x=18*2=36°

∠B=3x=18*3=54°

∠C=5x=18*5=90

hope it helps

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Answered by meenahajarilal95
3

Answer:

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