Question

in a ∆ABV, if <B=90°, AB=xcm, BC=ycm and AC=zcm, then with solution
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Answer 1

Answer:

We are given that in △ABC,∠=90

o

tyhe sides of △ABC is given by

AB=x cm,BC=(4x+4)cm &

AC=(4x+5) cm

From the pythagoras theorem,

AC

2

=AB

2

+BC

2

So,

(4x+5)

2

−(x)

2

+(4x+4)

2

16x

2

+40x+25=x

2

+16x

2

+22z−16

∴ 16x

2

+40x+25=17x

2

+32x+16

∴ x

2

−8x−9=0

∴ (x−9)(x+1)=0

∴ x=9 or x=−1

but distance cannot be negative

So, x=9

Now, sides are AB=x=9 cm

BC=4(9)+4=40 cm

AC=4(9)+5=41 cm

Step-by-step explanation:

Answer 2

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