In a ac circuit supply voltage and current are given as v=200sinwt and i=105 sin(wt-40), find the impedance in the circuit
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Bandwidth=R÷L
Again,
Bandwidth= resonating frequency (fr)÷ Q factor.
Q=(1/R )× (L/C)^1/2
=1÷100 ×(8/0.5)^1/2
=40
Now,100/8=fr/40
=fr=(100×40)÷8=4000/8=500rad/s (ans.)
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ℏ✺ℓᾰ ժḙᾰԻ
Given:
Resistance of the resistor, R = 100 Ω
Supply voltage, V = 220 V
Frequency, ν = 50 Hz
(a) The rms value of current in the circuit is given as
I= (V/R)
= (220)/ (100)
= 2.20 A
(b) The net power consumed over a full cycle is given as:
P = VI
= 220 × 2.2 = 484 W
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