In a Angel ABC, if Angel 2 . A = 3 Angle B = 6 C
calculate Angel A, Angel B and Angel C.
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Answer:
According to the condition in the △ABC, 2∠A=3∠B=6∠C
⇒∠A=3∠C and, ∠B=2∠C
Sum of interior angles of the triangle is 180
o
Hence ∠A+∠B+∠C=180
o
⇒3∠C+2∠C+∠C=180
o
⇒∠C=30
o
∴∠A=90
0
,∠B=60
o
,∠C=30
o
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