Question

In a angle ABC,internal bisector of <B and <C meet at a point O. if AC>AB, then prove that OC>OB​

Answer 1

Answer:

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Step-by-step explanation:

Given: OB and OC bisect ∠B and ∠C respectively.

In △BOC,

∠BOC+∠OBC+∠OCB=180 (OB and OC bisect ∠B and ∠C respectively)

∠BOC+  

2

1

​  

∠B+  

2

1

​  

∠C=180

∠BOC=180−  

2

1

​  

(∠B+∠C)

∠BOC=180−  

2

1

​  

(180−∠A) (Angle sum property)

∠BOC=90+  

2

1

​  

∠A

Answer 2

Step-by-step explanation:

explanation throughly