Question

In a APQR, PS is the angle bisector of
ZQPR, PQ = 4 cm, and RS = 6 cm.
_______cm is the value of
(PR X QS) = (PQ + RS).​

Answer 1

$\huge\rm\underline\purple{Solution :-}$

Let the base of the triangle be PQ=4 cm, then the height is RT=6 cm.

Hence area of triangle

$= \frac{1}{2} base \times height \: = \: \frac{1}{2} \times 4 \times 2 = 12 {cm}^{2}$

Now A = 12 cm²

Hence,

$\frac{1}{2} Pr \times QS = 12 \\ ⟹ \frac{1}{2} \times 8 \times QS = 12 \\ ⟹ \: QS = 3cm$