Math, asked by dhrubabebejiap35m28, 1 year ago

In a army camp ration available for600 soldier for 35 days.. After 10 days 300 more soldier come and reduce the ration availability 5:3.. how many days will last

Answers

Answered by streetburner
0

Step-by-step explanation:

600*35 = 600*10 + 900*(x)

21000 = 6000 + 900x

x = 15000/900 = 150/9

= 50/3

So total days = 10 + 50/3

= 80/3

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