Question

In a army camp there are 840soliders and there are enough food for70 days . After 5 days 210 soldiers joined in the army camp.Find the no.of days for which the food will be sufficient.

Answer 1

Answer:

1]let soldiersX=840

Step-by-step explanation:

days Y=70

2]let soldiers x=840+210=1050

days y=?

this is in indirectpropotion so formula is

XY=xy

840*70=1050*y

840*70/1050=y

168*7/21=y

168/3=y

56=y

Answer 2

Answer:

The number of days for which the food would be sufficient for 1050 soldiers is 52.

Step-by-step explanation:

Initially, the number of soldiers in the camp = 840

Consider that that one soldier eats one unit of food per day.

Initially, total units of food =$= 840\times 70 = 58800$

The amount of food consumed by 840 soldiers in 5 days = 4800 units.

∴ Amount of food left after 5 days$=58800-4800=54600 \;unit$

Total number of soldiers after five days = 840 + 210 = 1050

Number of days for which the food would be sufficient $= \frac{54600}{1050} =52\; days$

Therefore, the food will be sufficient for 52 days.

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