Math, asked by aga17, 10 months ago

In a bag are only red and white marbles. The probability of choosing a red marble is 3/5. The probability of choosing two red marbles without replacement is 3/10. How many white marbles are in the bag? Please help.

Answers

Answered by davenirbhay21
1

Answer:

hey mate here is your answer......

Step-by-step explanation:

If we let r and w be original # of red & white marbles,

P(red) = r/(r+w) = 3/5 which implies that r+w = (5/3)r ... Eq. One

On second draw w/o replacement, P(red,red) = (3/5)(r-1)/(r+w-1) = 3/10.

Therefore (r-1)/(r+w-1) = 1/2 ... Eq. Two.

By cross-multiplying we have 2r-2 = r+w-1 and into this we substitute from Eq. One for the expression (r+w):

2r - 2 = (5/3)r - 1

(1/3)r = 3 so r = 9.

If understood and got it please mark brainliestand yes

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