In a bag of 21 balls marked by numbers 1, 2, 3..........21. Two balls are drawn one by one with replacement. What is the probability that from drawn balls first shows odd number and second shows even number?
Answers
Answered by
0
Answer:
11/42……........................
Answered by
1
Answer:
Required Probablity =110/441
Step-by-step explanation:
Total number of balls =21
Number of balls marked even (2,4,6,..,20)=10
Number of balls marked odd (1,3,5,7,...21)=11
Thus required Probability = Probability of first odd × probability of second even
=11/21×10/21
Required Probablity =110/441
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