in a bag of red and blue balls, the number of Blue balls is 2 more than the red balls. how many red balls are there in the bag. if the total number of balls are 40.
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Let blue ball be x and red ball be y
Total No. of balls = 40
x + y = 40 (i)
x = 2 + y (ii)
Substitute eqn (ii) in eqn (i)
2 + y + y = 40
2 + 2y = 40
2y = 40 - 2
y = 38/2
y = 19
Substitute value of y in eqn (ii)
x = 2 + 19
x = 21
Blue balls = 21 and Red balls = 19
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