In a bag of RS 50 paise and 10 paise the paise the ratio is 3:4:8.if the total money in this bag is RS 116. Then what is the namber of 10 paise coins?
Answers
Answer:
The ratio of ₹1, 50 paise, and 10 paise in a purse is 3:4:8 respectively.
The total amount of money is ₹116 in the purse.
TO FIND :
The number of 10 paise in the purse.
SOLUTION :
Let's assume that number of :
➡ ₹1 is 3x.
➡ ₹0.50 is 4x.
➡ ₹0.10 is 8x.
Therefore,
Amount of :
➡ ₹1 will be 3x × ₹1 = ₹3x
➡ ₹0.50 will be 4x × ₹0.50 = ₹2x
➡ ₹0.10 will be 8x × ₹0.10 = ₹0.80x.
Now,
It's being told that total amount of money is ₹116 in the purse.
According to the question,
We can say that,
\begin{gathered}\implies \bf \: 3x \: + 2x \: + 0.80x = 116 \\\end{gathered}
⟹3x+2x+0.80x=116
\begin{gathered}\bf \implies \: 5.80x = 116 \\ \end{gathered}
⟹5.80x=116
\begin{gathered}\bf \implies \frac{580}{100} x = 116 \\\end{gathered}
⟹
100
580
x=116
\begin{gathered}\bf \implies x = \frac{\cancel{116} \times 10\cancel0}{\cancel{58} \cancel0} \\ \end{gathered}
⟹x=
58
0
116
×10
0
\bold \gray\dag{ \underline{ \boxed{ \green{ \bf \therefore \: x = 20}}}} \bold \gray\dag†
∴x=20
†
FINALLY,
We get x = 20
HENCE,
No. of ₹1 = 3x = 3 × 20 = 60.
No. of ₹0.50 = 4x = 4 × 20 = 80.
No. of ₹0.10 = 8x = 8 × 2
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