Question

In a bag their are 20 kg of fruit.lf 43/6kg of these fruit be orange and 26/3 kg of these are apple and rest are grapes. Find the mass of the grapes in a bag

Answer 1

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

A bag contains 20 kg of fruit in which 43/6 kg of orange , 26/3 kg of apple and rest are grapes present

Let ,

The mass of the grapes be "x" kg

According to the question ,

$\sf \hookrightarrow \frac{43}{6} + \frac{26}{3} + x = 20 \\ \\ \sf \hookrightarrow x = 20 - \frac{43}{6} - \frac{26}{3} \\ \\\sf \hookrightarrow x = \frac{120 - 43 - 52}{6} \\ \\ \sf \hookrightarrow x = \frac{120 - 95}{6} \\ \\\sf \hookrightarrow x = \frac{25}{6} \\ \\\sf \hookrightarrow x = 6.1 \: \: kg \: \: (approx)</p><p>$

Hence , the mass of the grapes is 6.1 kg

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Answer 2

Answer:

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Step-by-step explanation:

A bag contains 20 kg of fruit in which 43/6 kg of orange , 26/3 kg of apple and rest are grapes present

Let ,

The mass of the grapes be "x" kg

According to the question ,

\begin{gathered} \sf \hookrightarrow \frac{43}{6} + \frac{26}{3} + x = 20 \\ \\ \sf \hookrightarrow x = 20 - \frac{43}{6} - \frac{26}{3} \\ \\\sf \hookrightarrow x = \frac{120 - 43 - 52}{6} \\ \\ \sf \hookrightarrow x = \frac{120 - 95}{6} \\ \\\sf \hookrightarrow x = \frac{25}{6} \\ \\\sf \hookrightarrow x = 6.1 \: \: kg \: \: (approx) < /p > < p > \end{gathered}

↪

6

43

+

3

26

+x=20

↪x=20−

6

43

−

3

26

↪x=

6

120−43−52

↪x=

6

120−95

↪x=

6

25

↪x=6.1kg(approx)</p><p>

Hence , the mass of the grapes is 6.1 kg

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