Question

in a bag there are ₹1,₹2 and ₹10 coins in ratio 5:6:2 if in all there are 952 find the no. of each type of coin​

Answer 1

Answer:

A bag contains 1 rupee, 50 paise, and 25 paise coins in the ratio 5:6:8 amounting to Rs 210. What is the number of coins of each type?

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The value of 19 coins in the given ratio

5 ~ (5×1) = 5

6 ~ (6/2) = 3

8 ~(8/4) = 2

The total value =10

So value of 210 can be had by ~ (210/10) = 21 sets

i e (5×21)=105 ,(6×21)=126, (8×21)= 168

i e 105 nos of 1 rupee = 105

and 126 nos of 50 paise = 63

And 168 nos of 25 paise = 42

Total value = 105+63+42 = 210

Step-by-step explanation:

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Answer 2

Answer:

5x +6x +2x = 952

13x = 952

x = 952/13

x = 74 ( approx)

5x = 74*5 = 370

6x = 74*6= 464

2x = 74*2 = 148