in a bag there are 100 balls out of which 30 are defective once full will be taken out of the bag at random find the probability of the selected word to be a good one
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There are 15 bulbs; 10 are good; and 5 are defective.
Since we are choosing 3 at random, the total number of outcomes is 15C3.
The favorable cases are: selecting 2 good bulbs and 1 defective bulb.
Selecting 2 good bulb from 10 good bulbs is 10C2 and selecting 1 defective bulb from 5 defective bulbs is 5C1.
Therefore, the favorable cases are 5C1*10C2
Hence, the required probability is 5C1*10C2/15C3 = 45/91
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- Probability = (no. of favourable outcomes )/(total no. of outcomes)
= (100-30)/100
= 70/100 = 7/10
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