Question

In a bag there are 3 red balls, 4 black balls, 8 blue balls and 5 white balls.
What is the probability of getting
1) White Balls
2) Blue Balls
3) Red Balls
4) Not Black Balls​

Answer 1

Given :-

There are 3 red balls , 4 black balls , 8 blue balls and 5 white balls.

To find :-

What is the probability of getting

1) White balls

2) Blue balls

3) Red balls

4) Not Black balls

Solution :-

Given that

Number of Red balls in a bag = 3

Number of favourable outcomes to Red ball = 3

Number of Black balls in the bag = 4

Number of favourable outcomes to Black ball = 4

Number of Blue balls in the bag = 8

Number of favourable outcomes to Blue ball = 8

Number of White balls in the bag = 5

Number of favourable outcomes to White ball = 5

Number of all balls in the bag

= 3+4+8+5

= 20

We know that

Probability of an event E is P(E) = Number of favourable outcomes/Number of all possible outcomes

1) Probability of getting a White ball

P(W) = 5/20

=> P(W) = 1/4

2)Probability of getting a Blue ball

P(B) = 8/20

=> P(B) = 2/5

3) Probability of getting a Red ball

P(R) = 3/20

4) Number of favourable outcomes of getting a not black ball = All balls - Black balls

= 20-4

= 16

4) Probability of getting not a Black ball

=> P(not Black ) = 16/20

=> P(not Black ) = 4/5

Answer :-

1) Probability of getting a White ball = 1/4

2) Probability of getting a Blue ball = 2/5

3) Probability of getting a Red ball = 3/20

4) Probability of getting not a Black ball = 4/5

Used formulae:-

• Probability of an event E is P(E) = Number of favourable outcomes/Number of all possible outcomes

Answer 2

Answer:

Total balls= 3+4+8+5=20

Step-by-step explanation:

White= 5/20
Blue=8/20
Red=3/20
Not Black= black=4 then 20-4= 16 ans; 16/20
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