In a bag, there are 36 bulb out of which 12 are defective ones. A bulb is taken out of the bag at random. Find the probability of the selected bulb to be a good one
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Answered by
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Hii friend,
Possible outcomes = 36
Favourable outcomes = 36-12 = 24
P(E) getting a good bulbs = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES = 24/36= 2/3 Ans.
HOPE IT WILL HELP YOU.... :-)
Possible outcomes = 36
Favourable outcomes = 36-12 = 24
P(E) getting a good bulbs = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES = 24/36= 2/3 Ans.
HOPE IT WILL HELP YOU.... :-)
Answered by
1
Total number of bulbs = 36
Number of defective bulbs = 12
P(Getting a defective bulb) = 12/36
= 0.34
Therefore, the probability of getting a good bulb = 1 - 0.34
= 0.66 Ans
Number of defective bulbs = 12
P(Getting a defective bulb) = 12/36
= 0.34
Therefore, the probability of getting a good bulb = 1 - 0.34
= 0.66 Ans
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