In a bag there are 4 black and 6 orange 5 red balls probability
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Total balls i.e., sample space = 15
n(S)=15
B be the set representing black balls.
n(B)=4
So, P(B)=4/15
O be the set representing orange balls.
n(O)=6
P(O)=6/15
R be the set representing red balls
n(R)=5
P(R)=5/15=1/3
n(S)=15
B be the set representing black balls.
n(B)=4
So, P(B)=4/15
O be the set representing orange balls.
n(O)=6
P(O)=6/15
R be the set representing red balls
n(R)=5
P(R)=5/15=1/3
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