Question

In a bag, there are 4 red balls, 5 green balls and 7 blue balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?​

Answer 1

Answer:-

$\red{\bigstar}$ Probability that it is neither a red ball nor blue ball

$\large\leadsto\boxed{\sf{\dfrac{5}{16}}}$

• Given:-

Number of red balls = 4

Number of green balls = 5

Number of blue balls = 7

• To Find:-

The probability that it is neither red nor blue.

• Solution:-

Total number of balls in the bag = 4 + 5 + 7 → 16

$\pink{\bigstar}$ $\boxed{\sf{Probability = \dfrac{Total \: no. \: of \: outcomes}{No. \: of \: experiments}}}$

• Probability of red ball = 4/16

= 1/4

• Probability of green ball = 5/16

= 5/16

• Probability of blue ball = 7/16

= 7/16

$\pink{\bigstar}$ Event that the ball is neither red nor blue = Event that the ball will be green

→ Probability = 5/16