Question

in a bag there are 4 white 4 red and 2 green balls to are drawn at random what is the probability of at least one being red?​

Answer 1

Answer:

2/5

Step-by-step explanation:

Total number of balls in the bag = 4 + 4 + 2 =10

Total possible outcomes = Selection of 2 balls out of 10 balls

= 10C2

= 10 * 9 / 1 * 2

= 90 / 2

= 45.

Favorable outcomes = 1 green ball and 1 ball of other colour + 2 green balls

= 2C1 * 8C1 + 2C2

= 2 * 8 + 2 = 18

Therefore, Required probability

= 18/45

= 2/5

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Answer 2

Answer : 2/5

Total number of balls in the bag = 4 + 4 + 2 =10

probability of coming red ball = 4

Total possible outcomes = 10

4 2

10 = 5