Question

In a bag, there are 5 green, o black and 7 red pens. One pen is picked up randomly. What is the probability
that it is neither red nor green?​

Answer 1

Answer:

total outcomes= 12

no of outcomes= 0

p( black pens)=12/0

=0

Answer 2

S=G1,G2,G3,G4,G5,R1,R2,R3,R4,R5,R6,R7.

n(S)=13 Let A be the event to get neither red nor green.

A=0

n(A)=0

P(A)=n(A)/n(S)

=0/13